道路設計 (光線版) 003 - 拼圖
By Regina
at 2008-01-06T16:15
at 2008-01-06T16:15
Table of Contents
※ 引述《EIORU ()》之銘言:
這次六邊形有了一些變化
每邊長都是100KM
A 連AD 過F點對AD做垂直線交於點X
/\
/ | \ 連FD 過E點對FD做垂直線交於點Y
B/ |__\F
│ X| │ 連接AB BC CD FX EY
│ | │
│ | │ AB = BC = CD = 100km
│ | Y │
C\ | /E FX = 50√2km
\ | /
\/ EY = √[(DE)^2-(DY)^2]
D
= √[(DE)^2-(DF/2)^2]
= √{(DE)^2-[(√[(FX)^2+(XD)^2])/2]}
= 38.26 km (就...自己代入吧)
Total = AB + BC + CD + FX + EY
= 300 + 70.7 + 38.26
= 408.96 (km)
這個是目前想到最短造法 (注意三面建造之編牆皆在最長中軸之一側)
各位大大們可以在給點意見 找找最短造法囉~
--
這次六邊形有了一些變化
每邊長都是100KM
A 連AD 過F點對AD做垂直線交於點X
/\
/ | \ 連FD 過E點對FD做垂直線交於點Y
B/ |__\F
│ X| │ 連接AB BC CD FX EY
│ | │
│ | │ AB = BC = CD = 100km
│ | Y │
C\ | /E FX = 50√2km
\ | /
\/ EY = √[(DE)^2-(DY)^2]
D
= √[(DE)^2-(DF/2)^2]
= √{(DE)^2-[(√[(FX)^2+(XD)^2])/2]}
= 38.26 km (就...自己代入吧)
Total = AB + BC + CD + FX + EY
= 300 + 70.7 + 38.26
= 408.96 (km)
這個是目前想到最短造法 (注意三面建造之編牆皆在最長中軸之一側)
各位大大們可以在給點意見 找找最短造法囉~
--
Tags:
拼圖
All Comments
By Caitlin
at 2008-01-10T09:46
at 2008-01-10T09:46
By Caitlin
at 2008-01-13T02:00
at 2008-01-13T02:00
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