數學考卷~所有三角形都是等腰三角形 - 拼圖
By Poppy
at 2008-06-16T00:05
at 2008-06-16T00:05
Table of Contents
B
過程如下: |\
| \
| \F
有三個點A,B,C D| O/\
做一條角A的平分線L, 和一條BC邊的中垂線M | / \
L和M相交於O (AO不需要和OF的向量相同) |/ E \
做OD⊥AB,OE⊥AC A ▇▇▇▇▇▇C
並連上BO和CO
1. 因為∠DAO=∠EAO ∠ODA=∠OEA AO=AO 所以△ADO=△AEO => 所以DO=EO AD=AE
2. 因為OF=OF BF=CF ∠BFO=∠CFO 所以△BFO=△CFO => BO=CO
3. 因為BO=CO DO=EO ∠ODB=∠OEC=90度 所以△BDO=△CEO => BD=CE
4. 因為AD=AE BD=CE 所以 AB=AC 因此 △ABC為等腰
哪裡錯了...
--
過程如下: |\
| \
| \F
有三個點A,B,C D| O/\
做一條角A的平分線L, 和一條BC邊的中垂線M | / \
L和M相交於O (AO不需要和OF的向量相同) |/ E \
做OD⊥AB,OE⊥AC A ▇▇▇▇▇▇C
並連上BO和CO
1. 因為∠DAO=∠EAO ∠ODA=∠OEA AO=AO 所以△ADO=△AEO => 所以DO=EO AD=AE
2. 因為OF=OF BF=CF ∠BFO=∠CFO 所以△BFO=△CFO => BO=CO
3. 因為BO=CO DO=EO ∠ODB=∠OEC=90度 所以△BDO=△CEO => BD=CE
4. 因為AD=AE BD=CE 所以 AB=AC 因此 △ABC為等腰
哪裡錯了...
--
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拼圖
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