馬上測出你的「制塔」進度！ - 神魔之塔

懶人包

Let a_n：{0,1,2,3,4,5,6,7,8,9,10} → S be an increasing sequence

where S = {0, 3.12, 12.68, 20.98, 30.53, 36.84, 43.21
, 65.41, 82.96, 91.22, 100}

Then for any n€[0,9], m€[1,850], both natural numbers,

a summoner passing seal n with rank m has the following score:

score = a_n + (a_(n+1) - a_n) * (m/850)
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首先，看原始碼，抓到這列code

user_persentage = (chapter_percent + (upper_chapter_percentage -
chapter_percent) * level_percent).toFixed(2)

再去看 chapter_percent = chapter_persentage[user_chapter]
(進度百分比a_n) (進度n)

所以 chapter_persentage是list之類的東西

果不其然

chapter_persentage = [0, 3.12, 12.68, 20.98, 30.53, 36.84, 43.21, 65.41,
82.96, 91.22, 100]


接著看 upper_chapter_percentage

= chapter_persentage[parseInt(user_chapter) + 1]

其中parseInt(user_chapter)應該跟user_chapter一模一樣，應該怕你輸入非正整數

最後看 level_percent 調出 user_percentage = (level / max_level)

所以就拼湊出公式拉！(‧^ω^‧)

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