解放路西法小共鳴效益計算 - 神魔之塔
By Skylar Davis
at 2015-12-10T00:26
at 2015-12-10T00:26
Table of Contents
【金‧極 -- 懶人包】
三隻小共鳴 = 兩隻小共鳴的1.3倍
四隻小共鳴 = 三隻小共鳴的1.2倍
結論:越多小共鳴越廢(?
【懶人包】
基於一些正常假設(在正文),小共鳴的增傷效益有以下事情:
1.解放LCF*3(或解放LCF*2 & LUNA*1) =1.3倍 解放LCF*2(或解放LCF*1 & LUNA*1)
2.解放LCF*4(或解放LCF*3 & LUNA*1) =1.2倍 解放LCF*3(或解放LCF*2 & LUNA*1)
(等號左右邊的差異假設是魔族,EX:多放一隻LCF or 改放魔族)
這也難怪放常駐增傷的魔族效益一定大於多放一隻解放LCF(或是從0隻LUNA變成1隻LUNA)
【前言】
在有解放LCF消息前就想算一下,但是當時沒有一個好的歸納,原因是:比較基準。
我們在討論增傷倍率時,就是以增傷後除以增傷前,因此要去比較兩不同隊伍配置的增傷
大小時,要說清楚你比較的基準是什麼
昨天在ㄅㄏ看到LUNA共鳴效益低落快笑屬偶惹,他分子是LUNA開共鳴,分母是放LUNA但沒
開共鳴,算出來當然低,因為把LUNA的小共鳴倍率也當作分母除進去了
我一開始用最廣的設定,X隻光,Y隻魔,每隻攻擊力多少,共有幾隻LCF,是否有LUNA,
整個未知數大爆炸,很難分析,後來採取了以下方式得到了不錯結果
【分析】
假設隊伍光非魔的卡片基礎攻擊力總合 = a (純討論小共鳴,光非神也可納入)
魔的卡片基礎攻擊力總合 = b
解放路西法隻數 = n
先計算小共鳴攻擊力
(1) 沒有LUNA:
ATK = [(a-2100)*0.5 + 2100 + b]*n + (a-2100*n)*0.5
n+1
= ─── a + nb
2
(2) 有LUNA:
ATK = [(a-2100)*0.5 + 2100 + b]*(n+1) + (a-2100*n-1520)*0.5
n+2
= ─── a + (n+1)b + 290
2
^^^^^^^^^^^^^^^^^
遠大於290,且正是(1)式中代入n=n+1的結果
因此有個降低複雜度的假設:沒LUNA時,多放1隻LUNA 或 多放1隻解放LCF,效益一樣
也因為如此,之後我都只考慮n隻解放LCF的case(相當於n-1隻解放LCF、1隻LUNA)
P.S. 這邊不要覺得很奇怪說為什麼LCF明明攻擊力比LUNA高,但是(2)式卻比(1)式代入
n+1時還多290,因為這兩式的a不一樣
再來,開始討論:
(a) 隊伍中已有2隻解放LCF,要選擇多1隻解放LCF或是魔族呢?
魔族 + 2隻解放LCF = ATK = (3/2)a + 2b --- (A)
3隻解放LCF = ATK = 2a' + 3b' --- (B)
其中a' = a + 2100 (多了一隻解放LCF,光屬多2100)
b' = b - x (少了一隻魔族(ATK=x),魔族攻擊力少x)
再來,為了化簡討論以及符合常用隊伍配置,魔族通常只擺一隻,因此我們有
b' = 0 <=> b = x (被換掉的那隻就是魔族)
且 b 設為 2100 (魔族攻擊力在17XX~24XX飄動)
現在來看 (B) 2(a+2100) 2a+2b 1/2
─── = ───── = ──── = 1 + ────── ---(C)
(A) (3/2)a+2b (3/2)a+2b (3/2)+2(b/a)
這邊就可以看到,b = 2100比起整隊光屬攻擊力a,其值連一半都不到,而且b/a在
分母,因此可以推斷(C) < 1.333的(令b/a → 0),所以我才說大約1.3倍
(a) 隊伍中已有3隻解放LCF,要選擇多1隻解放LCF或是魔族呢?
魔族 + 3隻解放LCF = ATK = 2a + 3b --- (D)
4隻解放LCF = ATK = (5/2)a' + 4b' --- (E)
其中a' = a + 2100 (多了一隻解放LCF,光屬多2100)
b' = b - x (少了一隻魔族(ATK=x),魔族攻擊力少x)
再來,為了化簡討論以及符合常用隊伍配置,魔族通常只擺一隻,因此我們有
b' = 0 <=> b = x (被換掉的那隻就是魔族)
且 b 設為 2100 (魔族攻擊力在17XX~24XX飄動)
現在來看 (E) (5/2)(a+2100) (5/2)a+(5/2)b 1 - b/a
─── = ─────── = ─────── = 1 + ────── --(F)
(D) 2a+3b 2a+3b 4 + 6(b/a)
這邊就可以看到,b = 2100比起整隊光屬攻擊力a,其值連一半都不到,而且b/a在
分母是正的,分子是負的,因此可以推斷(F) < 1.25 的(令b/a → 0),所以我
懶人包說大約1.2倍是很客氣了...隨便帶個b/a去看,甚至只有1.15
---------------------------------------------------------------------------
總而言之,路路露是看在露娜的主動技去放的,如果純粹要小共鳴就別放了
周六路路我來拉~(‧^ω^‧)
--
三隻小共鳴 = 兩隻小共鳴的1.3倍
四隻小共鳴 = 三隻小共鳴的1.2倍
結論:越多小共鳴越廢(?
【懶人包】
基於一些正常假設(在正文),小共鳴的增傷效益有以下事情:
1.解放LCF*3(或解放LCF*2 & LUNA*1) =1.3倍 解放LCF*2(或解放LCF*1 & LUNA*1)
2.解放LCF*4(或解放LCF*3 & LUNA*1) =1.2倍 解放LCF*3(或解放LCF*2 & LUNA*1)
(等號左右邊的差異假設是魔族,EX:多放一隻LCF or 改放魔族)
這也難怪放常駐增傷的魔族效益一定大於多放一隻解放LCF(或是從0隻LUNA變成1隻LUNA)
【前言】
在有解放LCF消息前就想算一下,但是當時沒有一個好的歸納,原因是:比較基準。
我們在討論增傷倍率時,就是以增傷後除以增傷前,因此要去比較兩不同隊伍配置的增傷
大小時,要說清楚你比較的基準是什麼
昨天在ㄅㄏ看到LUNA共鳴效益低落快笑屬偶惹,他分子是LUNA開共鳴,分母是放LUNA但沒
開共鳴,算出來當然低,因為把LUNA的小共鳴倍率也當作分母除進去了
我一開始用最廣的設定,X隻光,Y隻魔,每隻攻擊力多少,共有幾隻LCF,是否有LUNA,
整個未知數大爆炸,很難分析,後來採取了以下方式得到了不錯結果
【分析】
假設隊伍光非魔的卡片基礎攻擊力總合 = a (純討論小共鳴,光非神也可納入)
魔的卡片基礎攻擊力總合 = b
解放路西法隻數 = n
先計算小共鳴攻擊力
(1) 沒有LUNA:
ATK = [(a-2100)*0.5 + 2100 + b]*n + (a-2100*n)*0.5
n+1
= ─── a + nb
2
(2) 有LUNA:
ATK = [(a-2100)*0.5 + 2100 + b]*(n+1) + (a-2100*n-1520)*0.5
n+2
= ─── a + (n+1)b + 290
2
^^^^^^^^^^^^^^^^^
遠大於290,且正是(1)式中代入n=n+1的結果
因此有個降低複雜度的假設:沒LUNA時,多放1隻LUNA 或 多放1隻解放LCF,效益一樣
也因為如此,之後我都只考慮n隻解放LCF的case(相當於n-1隻解放LCF、1隻LUNA)
P.S. 這邊不要覺得很奇怪說為什麼LCF明明攻擊力比LUNA高,但是(2)式卻比(1)式代入
n+1時還多290,因為這兩式的a不一樣
再來,開始討論:
(a) 隊伍中已有2隻解放LCF,要選擇多1隻解放LCF或是魔族呢?
魔族 + 2隻解放LCF = ATK = (3/2)a + 2b --- (A)
3隻解放LCF = ATK = 2a' + 3b' --- (B)
其中a' = a + 2100 (多了一隻解放LCF,光屬多2100)
b' = b - x (少了一隻魔族(ATK=x),魔族攻擊力少x)
再來,為了化簡討論以及符合常用隊伍配置,魔族通常只擺一隻,因此我們有
b' = 0 <=> b = x (被換掉的那隻就是魔族)
且 b 設為 2100 (魔族攻擊力在17XX~24XX飄動)
現在來看 (B) 2(a+2100) 2a+2b 1/2
─── = ───── = ──── = 1 + ────── ---(C)
(A) (3/2)a+2b (3/2)a+2b (3/2)+2(b/a)
這邊就可以看到,b = 2100比起整隊光屬攻擊力a,其值連一半都不到,而且b/a在
分母,因此可以推斷(C) < 1.333的(令b/a → 0),所以我才說大約1.3倍
(a) 隊伍中已有3隻解放LCF,要選擇多1隻解放LCF或是魔族呢?
魔族 + 3隻解放LCF = ATK = 2a + 3b --- (D)
4隻解放LCF = ATK = (5/2)a' + 4b' --- (E)
其中a' = a + 2100 (多了一隻解放LCF,光屬多2100)
b' = b - x (少了一隻魔族(ATK=x),魔族攻擊力少x)
再來,為了化簡討論以及符合常用隊伍配置,魔族通常只擺一隻,因此我們有
b' = 0 <=> b = x (被換掉的那隻就是魔族)
且 b 設為 2100 (魔族攻擊力在17XX~24XX飄動)
現在來看 (E) (5/2)(a+2100) (5/2)a+(5/2)b 1 - b/a
─── = ─────── = ─────── = 1 + ────── --(F)
(D) 2a+3b 2a+3b 4 + 6(b/a)
這邊就可以看到,b = 2100比起整隊光屬攻擊力a,其值連一半都不到,而且b/a在
分母是正的,分子是負的,因此可以推斷(F) < 1.25 的(令b/a → 0),所以我
懶人包說大約1.2倍是很客氣了...隨便帶個b/a去看,甚至只有1.15
---------------------------------------------------------------------------
總而言之,路路露是看在露娜的主動技去放的,如果純粹要小共鳴就別放了
周六路路我來拉~(‧^ω^‧)
--
Tags:
神魔之塔
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