節目上看到的骰子九宮格遊戲 - 拼圖
By Ophelia
at 2014-08-22T20:41
at 2014-08-22T20:41
Table of Contents
之前在網路上看到一個臺灣節目《真的!了不起》,
最後一個環節──十萬獎金挑戰賽的規則如下: ┌─┬─┬─┐
│1│2│3│
兩人一組的藝人來賓共同擲兩顆骰子(點數和=2~12), ├─┼─┼─┤
假設擲出點數和為N, │4│5│6│
可以消去九宮格中的數字N,或消去兩個總和為N的數字, ├─┼─┼─┤
如果能將九個數字剛好全部消除,即挑戰成功,獲得獎金; │7│8│9│
反之,只要無法消除數字就算挑戰失敗。 └─┴─┴─┘
看到目前還沒有人成功過,
藝人幾乎都是擲到大的數字先消(比如8或9就消8或9),
而且喜歡先把1這個數字消掉。
不知道這個遊戲比較好的策略為何?
甚至有辦法估算挑戰成功的機率嗎?
--
最後一個環節──十萬獎金挑戰賽的規則如下: ┌─┬─┬─┐
│1│2│3│
兩人一組的藝人來賓共同擲兩顆骰子(點數和=2~12), ├─┼─┼─┤
假設擲出點數和為N, │4│5│6│
可以消去九宮格中的數字N,或消去兩個總和為N的數字, ├─┼─┼─┤
如果能將九個數字剛好全部消除,即挑戰成功,獲得獎金; │7│8│9│
反之,只要無法消除數字就算挑戰失敗。 └─┴─┴─┘
看到目前還沒有人成功過,
藝人幾乎都是擲到大的數字先消(比如8或9就消8或9),
而且喜歡先把1這個數字消掉。
不知道這個遊戲比較好的策略為何?
甚至有辦法估算挑戰成功的機率嗎?
--
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