機率問題---三個門後的羊&車 - 拼圖

By Lily
at 2005-10-04T14:33
at 2005-10-04T14:33
Table of Contents
※ 引述《leondemon (狗狗)》之銘言:
: 所以答案無論你換不換門 機率依然是一開始的1/3
又是一個一知半解的人...
機率學的三大假設
1. 0<=P(任一事件)<=1
2. P(空集合)=0, P(全集合)=1
3. 機率總合為1。
即 P(轎車在原先選的門內)+P(轎車在另一個未開的門內)=1
所以,換門和不換門的機率和會為1,
不可能兩個機率會是1/3!
事實上
不換門, P(轎車在原先選的門內)=1/3
換門, P(轎車在另一個未開的門內)=2/3
--
: 所以答案無論你換不換門 機率依然是一開始的1/3
又是一個一知半解的人...
機率學的三大假設
1. 0<=P(任一事件)<=1
2. P(空集合)=0, P(全集合)=1
3. 機率總合為1。
即 P(轎車在原先選的門內)+P(轎車在另一個未開的門內)=1
所以,換門和不換門的機率和會為1,
不可能兩個機率會是1/3!
事實上
不換門, P(轎車在原先選的門內)=1/3
換門, P(轎車在另一個未開的門內)=2/3
--
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拼圖
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