TurkZeka 2009 (10) - 拼圖

By Elizabeth
at 2009-07-29T10:02
at 2009-07-29T10:02
Table of Contents
帕索大真厲害
竟然還看出這些數字之間隱藏了一個槓桿原理的關係
我沒看出來耶,但是答案還是做出來了(汗)
我來試著解一下這九個數字吧
(1-9)
a□□b■□□□c 橫一
□□□□□□□□□
□□□□□□□□□
d□□e□■□□f 橫二
□□□□□□□□□
□□□■□□□□■
■□□□□□□□□
□□□□□□□□□
□□□□□□□□□
g□□h■□□□i 橫三
直 直 直
一 二 三
首先,先看橫一, 4a+b=4c,右邊是四的倍數,左邊也必是四的倍數,b不是4就是8
再看橫三,4g+h = 4i,同理,h不是4就是8
再看直二, 2e+5b = 4h
若b是8,h則為4,2e+40 = 16,e = -12(不合)
故b是4,h為8, 2e+20 = 32, e = 6
再看橫二,5d+2e = 3f → 5d+12 = 3f ,右邊是三的倍數,左邊也必是三的倍數
故d = 3,5x3+12 = 3f → 27 = 3f,f = 9
至此,3,4,6,8,9都已被拿走,只剩1,2,5,7
橫一算式:4a+4 = 4c → a+1 = c ,a跟c差1
橫三算式:4g+8 = 4i → g+2 = i, i跟g差2
剩下的四個數字1,2,5,7,剛好1跟2差1,5跟7差2
a = 1, c = 2, g = 5, i = 7
代入直一跟直三驗算
直一:6a+3d = 3g → 6x1 + 3x3 = 3x5(合)
直三:5c+2f = 4i → 5x2 + 2x9 = 4x7(合)
故 a = 1, b = 4, c = 2, d = 3, e = 6, f = 9, g = 5, h =8, i = 7
1□□4■□□□2
□□□□□□□□□
□□□□□□□□□
3□□6□■□□9
□□□□□□□□□
□□□■□□□□■
■□□□□□□□□
□□□□□□□□□
□□□□□□□□□
5□□8■□□□7
--
Tags:
拼圖
All Comments

By Franklin
at 2009-08-02T13:55
at 2009-08-02T13:55

By Sandy
at 2009-08-07T07:35
at 2009-08-07T07:35
Related Posts
TurkZeka 2009 (10)

By Carol
at 2009-07-28T09:48
at 2009-07-28T09:48
[橋藝]雙夢家謎NO.9+10

By Puput
at 2009-07-27T22:09
at 2009-07-27T22:09
[橋藝]雙夢家謎NO.9+10

By Joseph
at 2009-07-27T20:50
at 2009-07-27T20:50
[橋藝]雙夢家謎NO.9+10

By Linda
at 2009-07-27T18:33
at 2009-07-27T18:33
[橋藝]雙夢家謎NO.9+10

By John
at 2009-07-27T13:09
at 2009-07-27T13:09