TurkZeka 2009 (10) - 拼圖

By Noah
at 2009-07-22T19:05
at 2009-07-22T19:05
Table of Contents
我本來以為blocks愈多愈好
剛才算了一下
blocks是34或36為最佳解
假設 blocks的數目為2x (因為水平跟垂直的blocks數目要一樣,所以必為偶數)
blocks所佔的格子數為2x * 3 = 6x
剩下的格子數是path路徑,為210-6x
假設每個格子的平均分數是3,這當然是高估了,我剛才做了2次
格子的平均分數只有2.4~2.5
之前推文說做到3萬分的仁兄,格子的平均分數也只有2.79
範例中的格子平均分數甚至不超過2分
因此取3為最大值
所以總分為 (210-6x)*3*2x*3
= 108 [(35-x)x]
= 108 [1225/4-(x-35/2)^2]
x必須是整數,當x=17或18時有最大值 33048
故最佳blocks是34或36
--
剛才算了一下
blocks是34或36為最佳解
假設 blocks的數目為2x (因為水平跟垂直的blocks數目要一樣,所以必為偶數)
blocks所佔的格子數為2x * 3 = 6x
剩下的格子數是path路徑,為210-6x
假設每個格子的平均分數是3,這當然是高估了,我剛才做了2次
格子的平均分數只有2.4~2.5
之前推文說做到3萬分的仁兄,格子的平均分數也只有2.79
範例中的格子平均分數甚至不超過2分
因此取3為最大值
所以總分為 (210-6x)*3*2x*3
= 108 [(35-x)x]
= 108 [1225/4-(x-35/2)^2]
x必須是整數,當x=17或18時有最大值 33048
故最佳blocks是34或36
--
Tags:
拼圖
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at 2009-07-23T07:42
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