請問一數學機率問題 - 拼圖

By Necoo
at 2013-10-20T11:56
at 2013-10-20T11:56
Table of Contents
那我把我的想法說出來
第一顆球有6個洞可以選擇
第二顆球則剩5個洞可以選擇
所以一開始的機率為6*5*4*3*2*1
由於黑白球都為相同所以還要除3!*3!
所以有20個排列方法
接下來一開始先抽到白球
為了求下個拿出來的是黑球
所以我把黑白球固定好
接下來就剩下2黑2白可以排
所以用上述的想法地已得到
(4*3*2*1)/2!*2!=6
所以可以得到
6/20的機率=3/10
--
第一顆球有6個洞可以選擇
第二顆球則剩5個洞可以選擇
所以一開始的機率為6*5*4*3*2*1
由於黑白球都為相同所以還要除3!*3!
所以有20個排列方法
接下來一開始先抽到白球
為了求下個拿出來的是黑球
所以我把黑白球固定好
接下來就剩下2黑2白可以排
所以用上述的想法地已得到
(4*3*2*1)/2!*2!=6
所以可以得到
6/20的機率=3/10
--
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