現在Buddy里程停在哪會比較賺? - PokemonGO

By Frederic
at 2017-05-18T20:29
at 2017-05-18T20:29
Table of Contents
補充 :
有鑑於現代人生活忙碌, 直接給出公式(假設預計行走目標都至少等於夥伴找糖需公里數)
3
如果本來預計行走目標走完後, 最後未換糖里程 < (---)*夥伴找糖需公里數
4
3
則不如走到最後一次未換糖里程是 (---)*夥伴找糖需要公里數 後就休息不要走完
4
3
如果本來預計行走目標走完後, 最後未換糖里程 ≧ (---)*夥伴找糖需公里數,則建議走完
4
--
※ 引述《nan36 (南)》之銘言:
: 如果是休閒型玩家,每天里程數不多
: 正在遛5km的寵,現在里程差不多在4.9km
: 如果停下來等4點活動開始,反而可多賺3顆糖
: 請問各位大師,這樣對嗎?
不對, 假如你本來還會繼續走卻因為要等活動而故意停
得到的總糖量反而可能比原來少
以 5 km 寵舉例
設目前累計里程 x km (0 ≦ x < 5), 活動開始前按個人生活習慣本來還預計走 y km
x + y
則活動前可得糖 [-------] 顆
5
4 x + y
活動剛開始可再得 [--- * (x + y - 5 * [-------])] 顆
5 5
x + y 4 x + y
總糖數為 f(x,y) = [-------] + [--- * (x + y - 5 * [-------])] 顆
5 5 5
其函數圖形在二維的等高線圖用軟體畫出為這樣 : http://i.imgur.com/gbAO4VO.gif
顏色越淺代表在該點函數值越大
注意到給定任意 x = a 時, f(a,y) 皆為階梯函數
(如 x = 3 時 : http://i.imgur.com/6z4cVBz.png )
且其規律為先遞增, 但是每些區段會陡降, 之後再次遞增 , 再陡降.... 一直重複下去
( Remark : 陡降的區間長度皆恰為 15/4 )
因此只要你的 y 會造成原函數掉到陡降的區間, 那不如走比 y 還少反而糖果會比較多!
例如 : x = 3 時, 走 2 ≦ y < 5.75 km 不如走到 1.9 km 就休息糖果還比較多(或一樣)
但假如你的 y 不是落在會造成原函數掉到陡降的區間, 那你應該要繼續走糖才會比較多!
例如 : x = 3 時, 走 y = 6 km 會比 走 0 < y < 6 km 得到的糖都多
綜合以上, 回到原問題
假如現在里程差不多在 4.9 km
如果你本來還打算走 0.1 ≦ y < 0.1 + 15/4 = 3.85 km
不如直接休息糖果會比較多或至少一樣
如果你本來還打算走 3.85 ≦ y < 5.1 km
那繼續走你才會得到較多糖果
其他情況仿上討論皆可解答
--
認真就輸了系列之 2
--
作者 qqkerk (江雨) 看板 PokemonGO
標題 [心得] 有朋友也對於尾立很失望嗎?
時間 Thu Mar 23 10:01:28 2017
───────────────────────────────────────
--
有鑑於現代人生活忙碌, 直接給出公式(假設預計行走目標都至少等於夥伴找糖需公里數)
3
如果本來預計行走目標走完後, 最後未換糖里程 < (---)*夥伴找糖需公里數
4
3
則不如走到最後一次未換糖里程是 (---)*夥伴找糖需要公里數 後就休息不要走完
4
3
如果本來預計行走目標走完後, 最後未換糖里程 ≧ (---)*夥伴找糖需公里數,則建議走完
4
--
※ 引述《nan36 (南)》之銘言:
: 如果是休閒型玩家,每天里程數不多
: 正在遛5km的寵,現在里程差不多在4.9km
: 如果停下來等4點活動開始,反而可多賺3顆糖
: 請問各位大師,這樣對嗎?
不對, 假如你本來還會繼續走卻因為要等活動而故意停
得到的總糖量反而可能比原來少
以 5 km 寵舉例
設目前累計里程 x km (0 ≦ x < 5), 活動開始前按個人生活習慣本來還預計走 y km
x + y
則活動前可得糖 [-------] 顆
5
4 x + y
活動剛開始可再得 [--- * (x + y - 5 * [-------])] 顆
5 5
x + y 4 x + y
總糖數為 f(x,y) = [-------] + [--- * (x + y - 5 * [-------])] 顆
5 5 5
其函數圖形在二維的等高線圖用軟體畫出為這樣 : http://i.imgur.com/gbAO4VO.gif
顏色越淺代表在該點函數值越大
注意到給定任意 x = a 時, f(a,y) 皆為階梯函數
(如 x = 3 時 : http://i.imgur.com/6z4cVBz.png )
且其規律為先遞增, 但是每些區段會陡降, 之後再次遞增 , 再陡降.... 一直重複下去
( Remark : 陡降的區間長度皆恰為 15/4 )
因此只要你的 y 會造成原函數掉到陡降的區間, 那不如走比 y 還少反而糖果會比較多!
例如 : x = 3 時, 走 2 ≦ y < 5.75 km 不如走到 1.9 km 就休息糖果還比較多(或一樣)
但假如你的 y 不是落在會造成原函數掉到陡降的區間, 那你應該要繼續走糖才會比較多!
例如 : x = 3 時, 走 y = 6 km 會比 走 0 < y < 6 km 得到的糖都多
綜合以上, 回到原問題
假如現在里程差不多在 4.9 km
如果你本來還打算走 0.1 ≦ y < 0.1 + 15/4 = 3.85 km
不如直接休息糖果會比較多或至少一樣
如果你本來還打算走 3.85 ≦ y < 5.1 km
那繼續走你才會得到較多糖果
其他情況仿上討論皆可解答
--
認真就輸了系列之 2
--
作者 qqkerk (江雨) 看板 PokemonGO
標題 [心得] 有朋友也對於尾立很失望嗎?
時間 Thu Mar 23 10:01:28 2017
───────────────────────────────────────
推 december1952: Furret大,有人對你很失望~XDDD 03/23 10:43
推 furret: 他在說Sentret 不是我03/23 11:50
--
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