數獨

數獨又卡關了 - 數獨

John avatarJohn · 2020-08-02

Table of Contents

https://i.imgur.com/YHGiBwE.jpg

反覆重解了幾次
還是卡在一樣的地方
求推解:(

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數獨

All Comments

Mary avatarMary2020-08-07
1. C1R678/C6R67/C9R78 HAS 6, C234R678 NO 6
Caitlin avatarCaitlin2020-08-09
2. C1R4 C3R6 HAS 39, C3R4=5
Zanna avatarZanna2020-08-13
1. 考慮R1和R8的4, R1C3(4,6)=>R8C2(4,5,6)不能是6。因為
會變成非唯一解
Odelette avatarOdelette2020-08-16
2. R1C3(4,6),R8C2(4,5) and R9C3(5,6)=>R1C3=4 or R8C2=
4 => R8C3 不是 4