[問題] 一項數學挑戰 - 拼圖

By Lily
at 2010-02-01T17:36
at 2010-02-01T17:36
Table of Contents
※ 引述《Huntelaar (Klaas Jan Huntelaar !!)》之銘言:
: : |----+----+----+----+------|
: : | 2 | 3 | 4 | 15 | 12 |
: : |----+----+----+----+------|
: : | 3 | 4 | 5 | 28 | 20 |
: : |----+----+----+----+------|
: : | 4 | 5 | 6 | 45 | 30 |
: : |----+----+----+----+------|
: : | 5 | 6 | 7 | 66 | 42 |
: : |----+----+----+----+------|
: : | 6 | 7 | 8 | ? | 56 |
: : |----+----+----+----+------|
: n n+1 n+2 (n+(n+1))*(n+1) (n+1)(n+2)
: 這是我想到的解法,雖然覺得很沒有邏輯(因為第四行跟第五行感覺沒有關係)
: 所以答案我認為是(6+7)*7=91
我的解法是先看最後一排發現
12 = 3 * 4
20 = 4 * 5
30 = 5 * 6
42 = 6 * 7
56 = 7 * 8
再看倒數第二排
15 = 3 * 5
28 = 4 * 7
45 = 5 * 9
66 = 6 * 11
?? = 7 * 13
?? = 91
--
: : |----+----+----+----+------|
: : | 2 | 3 | 4 | 15 | 12 |
: : |----+----+----+----+------|
: : | 3 | 4 | 5 | 28 | 20 |
: : |----+----+----+----+------|
: : | 4 | 5 | 6 | 45 | 30 |
: : |----+----+----+----+------|
: : | 5 | 6 | 7 | 66 | 42 |
: : |----+----+----+----+------|
: : | 6 | 7 | 8 | ? | 56 |
: : |----+----+----+----+------|
: n n+1 n+2 (n+(n+1))*(n+1) (n+1)(n+2)
: 這是我想到的解法,雖然覺得很沒有邏輯(因為第四行跟第五行感覺沒有關係)
: 所以答案我認為是(6+7)*7=91
我的解法是先看最後一排發現
12 = 3 * 4
20 = 4 * 5
30 = 5 * 6
42 = 6 * 7
56 = 7 * 8
再看倒數第二排
15 = 3 * 5
28 = 4 * 7
45 = 5 * 9
66 = 6 * 11
?? = 7 * 13
?? = 91
--
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拼圖
All Comments

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