STA - 魔法風雲會

By Zora
at 2012-07-08T08:31
at 2012-07-08T08:31
Table of Contents
想問一下State-based actions的檢查時機到底是?
會出現這樣的疑問主要是因為看到官方的FAQ
關於傑斯3.0 第三招,FAQ內的敘述是這樣的:
* 如果傑斯的第三個異能使得某玩家要抽取的牌張數目比他牌庫中的牌還要多,則他會由
於狀態動作而輸掉這盤遊戲。如果此異能使得所有玩家都面臨此狀況,此盤遊戲為平手。
然後又在CardWalker的某篇Q&A文章內看到這一題:
[Q]我的對手和我都操控實驗室狂人。如果他的牌庫的牌比我多,那我要如何施放興旺才
能贏呢?或者至少造成和局?
[A]你可以狂笑一陣,並且獲得遊戲的勝利!這裡重要的第一點是,當有東西告訴玩家抽
複數張牌時,它會是以一系列的抽一張來完成(因此「抽兩張牌」實際上是「抽一張牌,
然後抽一張牌」)。興旺會創造一系列的抽牌,造成某人從無牌的牌庫抽牌並且靠狂人獲
勝。
重要的第二點是,當"兩個"玩家都要抽牌時,他們並不是同時抽牌的。取而代之的是,就
和魔法風雲會裡面大多數的東西一樣,主動玩家會先抽正確數量的牌,然後非主動玩家再
抽正確數量的牌。這也表示(因為你應該會在自己回合施放興旺)你會在對手之前抽完牌
,所以如果這發興旺夠大讓你可以抽乾牌庫,你就會贏。
PS.我查不到"興旺"這張牌,不過應該是each Player draw X cards之類的吧?
我所知道的STA,它不管異能結算的過程發生了什麼事,它只在乎結果
704.4. Unlike triggered abilities, state-based actions pay no attention to
what happens during the resolution of a spell or ability.
這一條應該就是這個意思?
既然如此的話,不是實驗室狂人那個CASE應該也是個和局吧?
還是我誤會了其中的某事?
--
Tags:
魔法風雲會
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