5000鏈接石的決鬥 - 流亡黯道
By Steve
at 2018-10-25T22:11
at 2018-10-25T22:11
Table of Contents
簡單講一下我要銃啥
先算出點5000fus中幾個6L的標準差
利用常態分佈大數法則68-95-99.7法則來估算歐洲人非洲人的比例
(np(1-p))^(1/2)
先算一下標準差5000*(1/1200)*(1199/1200)再開跟號=2.04(先取到小數第二位)
假設有1000人每個人都點5000fus(?o?)
期望值是5000/1200=4.17
會有341人點到(4.17-2.04)到(4.17)件6連
341 (4.17)到(4.17+2.04)
136 (4.17-4.08)到(4.17-2.04)
136 (4.17+2.04)to(4.17+4.08)
23 (0)to(0.11)
23 8以上
-----------------------------------------------------
懶人包
大概3成的人點2-4件
3 4-6
1成多 0-2
1成多 6-8
2%多 0
2%多 8以上
所以結論就是還算是OK吧XD
所以玩十季的話 會有一季5000fus可以點6-8件 蠻爽的XD
感謝收看嚕
--
「不可能贏的吧,我也沒要想贏,我殺了你逃走之後又能怎麼樣?
可以改變什麼?重要的東西一樣都保護不了,根本沒有出口,
這種循環我已經不想再經歷了,所以拜託你,由你來結束吧
「(脫)我活下去的意義,是你給我的刻下的印記
「如果這個世界不是無限的地獄,那是因為有你啊~Phantom Requiem for the Phantom
--
先算出點5000fus中幾個6L的標準差
利用常態分佈大數法則68-95-99.7法則來估算歐洲人非洲人的比例
(np(1-p))^(1/2)
先算一下標準差5000*(1/1200)*(1199/1200)再開跟號=2.04(先取到小數第二位)
假設有1000人每個人都點5000fus(?o?)
期望值是5000/1200=4.17
會有341人點到(4.17-2.04)到(4.17)件6連
341 (4.17)到(4.17+2.04)
136 (4.17-4.08)到(4.17-2.04)
136 (4.17+2.04)to(4.17+4.08)
23 (0)to(0.11)
23 8以上
-----------------------------------------------------
懶人包
大概3成的人點2-4件
3 4-6
1成多 0-2
1成多 6-8
2%多 0
2%多 8以上
所以結論就是還算是OK吧XD
所以玩十季的話 會有一季5000fus可以點6-8件 蠻爽的XD
感謝收看嚕
--
「不可能贏的吧,我也沒要想贏,我殺了你逃走之後又能怎麼樣?
可以改變什麼?重要的東西一樣都保護不了,根本沒有出口,
這種循環我已經不想再經歷了,所以拜託你,由你來結束吧
「(脫)我活下去的意義,是你給我的刻下的印記
「如果這個世界不是無限的地獄,那是因為有你啊~Phantom Requiem for the Phantom
--
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